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Index  »  Projects  »  phpMyEdit  »  Forum  »  Can't filter records in a report

phpMyEdit General     Can't filter records in a report
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StephanieM     Joined: 08 Feb 2005   Posts: 9  
Post Posted: 2005-10-13 20:08
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Finally got the report extension to work, but can't filter records. In the field selection screen I should (?) be able to enter strings to be matched (?) next to each field. No matter what I enter, all records are always selected.

In addition, if I limit display to n records per page, the Next button is enabled but doesn't do anything.

Mac OS X 10.4 (Tiger, Safari 2.0). Also Firefox.

Help!

 
adamh     Joined: 28 Oct 2005   Posts: 2  
Post Posted: 2005-11-03 23:02
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I'm having the same problem. Using latest cvs, running Firefox on Linux. Anyone have any ideas?

 
sstewart     Joined: 15 Oct 2007   Posts: 4  
Post Posted: 2007-10-27 01:11
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I'm experiencing the same problem. Anyone got a fix for this yet?

 
mikehogl     Joined: 20 Apr 2009   Posts: 2  
Post Posted: 2009-04-20 17:51
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I'm having the same problem described here. Has anyone with a working Report extension able to filter records?

Other minor errors I'm seeing with my report function are:
-The Prev/Next Buttons do not work (are greyed out) if report is created with less records per page than exist in the db
-Number of records currently shows "Records: up" above the output report or "Records: down" below the outputted report instead of the number


But the filtering is my top priority if anyone can help. Thanks in advance.

 
sagiben     Joined: 27 Jan 2009   Posts: 15  
Post Posted: 2009-05-02 16:08
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I also have the same problem,
but actually I think that I found the cause,
still don't know how to fix it but I'm working on it.

phpMyEdit report extension doesn't do anything with the qf variables that are being passed to it in the address bar.

 
sagiben     Joined: 27 Jan 2009   Posts: 15  
Post Posted: 2009-05-14 17:18
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Hi,

I think I found the solution for the report extension does not filter records :
line 277 should be changed to :
Code:
          $varname = 'PME_sys_qf'.$i;

from
Code:
           $varname = 'qf'.$i;


 
mikehogl     Joined: 20 Apr 2009   Posts: 2  
Post Posted: 2009-05-14 18:50
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AWESOME, thanks for finding this. Works great!

 
Skipper     Joined: 20 Aug 2009   Posts: 7  
Post Posted: 2009-08-25 15:13
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see for working code also here
http://opensource.platon.sk/forum/projects/viewtopic.php?t=92921

 
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